-16x^2+7x+7=0

Solution for -16x^2+7x+7=0 equation:

-16x^2+7x+7=0

a = -16; b = 7; c = +7;
Δ = b2-4ac
Δ = 72-4·(-16)·7
Δ = 497
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{497}}{2*-16}=\frac{-7-\sqrt{497}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{497}}{2*-16}=\frac{-7+\sqrt{497}}{-32}
$